{ "cells": [ { "cell_type": "markdown", "id": "13af3d73", "metadata": {}, "source": [ "# Chirp-Scan" ] }, { "cell_type": "markdown", "id": "dc928827", "metadata": {}, "source": [ "### Z-Gradient \n", "\n", "1. SHG \n", "\n", " $\\frac{dS_{mk}}{dE_n^*} = 0$ \n", "\n", " $\\frac{dS_{mk}}{dE_n} = 2 D_{kn} A_{mk} e^{i\\phi_{mn}}$\n", "\n", "
\n", "\n", "2. THG \n", "\n", " $\\frac{dS_{mk}}{dE_n^*} = 0$ \n", "\n", " $\\frac{dS_{mk}}{dE_n} = 3 D_{kn} A_{mk}^2 e^{i\\phi_{mn}}$\n", "\n", "
\n", "\n", "3. PG/SD \n", "\n", " $\\frac{dS_{mk}}{dE_n^*} = D_{nk} A_{mk}^2 e^{-i\\phi_{mn}}$ \n", "\n", " $\\frac{dS_{mk}}{dE_n} = 2 D_{kn} |A_{mk}|^2 e^{i\\phi_{mn}}$\n", "\n", "
\n", "\n", "5. nth-HG \n", "\n", " $\\frac{dS_{mk}}{dE_n^*} = 0$ \n", "\n", " $\\frac{dS_{mk}}{dE_n} = n\\cdot D_{kn} A_{mk}^{n-1} e^{i\\phi_{mn}}$" ] }, { "cell_type": "markdown", "id": "2c56c9e0", "metadata": {}, "source": [ "### Z-Pseudo-Hessian \n", "\n", "1. SHG \n", "\n", " $V_{zz}=0$\n", " \n", "
\n", "\n", "2. THG \n", "\n", " $V_{zz}=0$\n", "\n", "
\n", "\n", "3. PG/SD\n", "\n", " $\\frac{d}{dE_p}\\left(\\frac{dS_{mk}}{dE_n}\\right)^* = 2D_{nk}D_{kp} A_{mk}^* e^{-i \\phi_{mn}} e^{i \\phi_{mp}}$\n", "\n", " $\\frac{d}{dE_p^*}\\left(\\frac{dS_{mk}}{dE_n^*}\\right)^* = 2D_{kn}D_{pk} A_{mk}^* e^{i \\phi_{mn}} e^{-i \\phi_{mp}}$\n", "\n", "\n", "
\n", "\n", "4. nth-HG \n", " \n", " $V_{zz} = 0$" ] } ], "metadata": { "language_info": { "name": "python" } }, "nbformat": 4, "nbformat_minor": 5 }