{
"cells": [
{
"cell_type": "markdown",
"id": "13af3d73",
"metadata": {},
"source": [
"# Chirp-Scan"
]
},
{
"cell_type": "markdown",
"id": "dc928827",
"metadata": {},
"source": [
"### Z-Gradient \n",
"\n",
"1. SHG \n",
"\n",
" $\\frac{dS_{mk}}{dE_n^*} = 0$ \n",
"\n",
" $\\frac{dS_{mk}}{dE_n} = 2 D_{kn} A_{mk} e^{i\\phi_{mn}}$\n",
"\n",
"
\n",
"\n",
"2. THG \n",
"\n",
" $\\frac{dS_{mk}}{dE_n^*} = 0$ \n",
"\n",
" $\\frac{dS_{mk}}{dE_n} = 3 D_{kn} A_{mk}^2 e^{i\\phi_{mn}}$\n",
"\n",
"
\n",
"\n",
"3. PG/SD \n",
"\n",
" $\\frac{dS_{mk}}{dE_n^*} = D_{nk} A_{mk}^2 e^{-i\\phi_{mn}}$ \n",
"\n",
" $\\frac{dS_{mk}}{dE_n} = 2 D_{kn} |A_{mk}|^2 e^{i\\phi_{mn}}$\n",
"\n",
"
\n",
"\n",
"5. nth-HG \n",
"\n",
" $\\frac{dS_{mk}}{dE_n^*} = 0$ \n",
"\n",
" $\\frac{dS_{mk}}{dE_n} = n\\cdot D_{kn} A_{mk}^{n-1} e^{i\\phi_{mn}}$"
]
},
{
"cell_type": "markdown",
"id": "2c56c9e0",
"metadata": {},
"source": [
"### Z-Pseudo-Hessian \n",
"\n",
"1. SHG \n",
"\n",
" $V_{zz}=0$\n",
" \n",
"
\n",
"\n",
"2. THG \n",
"\n",
" $V_{zz}=0$\n",
"\n",
"
\n",
"\n",
"3. PG/SD\n",
"\n",
" $\\frac{d}{dE_p}\\left(\\frac{dS_{mk}}{dE_n}\\right)^* = 2D_{nk}D_{kp} A_{mk}^* e^{-i \\phi_{mn}} e^{i \\phi_{mp}}$\n",
"\n",
" $\\frac{d}{dE_p^*}\\left(\\frac{dS_{mk}}{dE_n^*}\\right)^* = 2D_{kn}D_{pk} A_{mk}^* e^{i \\phi_{mn}} e^{-i \\phi_{mp}}$\n",
"\n",
"\n",
"
\n",
"\n",
"4. nth-HG \n",
" \n",
" $V_{zz} = 0$"
]
}
],
"metadata": {
"language_info": {
"name": "python"
}
},
"nbformat": 4,
"nbformat_minor": 5
}